(3x^2+x-1)(2x-3)=0

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Solution for (3x^2+x-1)(2x-3)=0 equation: 


Simplifying
(3x2 + x + -1)(2x + -3) = 0

Reorder the terms:
(-1 + x + 3x2)(2x + -3) = 0

Reorder the terms:
(-1 + x + 3x2)(-3 + 2x) = 0

Multiply (-1 + x + 3x2) * (-3 + 2x)
(-1(-3 + 2x) + x(-3 + 2x) + 3x2 * (-3 + 2x)) = 0
((-3 * -1 + 2x * -1) + x(-3 + 2x) + 3x2 * (-3 + 2x)) = 0
((3 + -2x) + x(-3 + 2x) + 3x2 * (-3 + 2x)) = 0
(3 + -2x + (-3 * x + 2x * x) + 3x2 * (-3 + 2x)) = 0
(3 + -2x + (-3x + 2x2) + 3x2 * (-3 + 2x)) = 0
(3 + -2x + -3x + 2x2 + (-3 * 3x2 + 2x * 3x2)) = 0
(3 + -2x + -3x + 2x2 + (-9x2 + 6x3)) = 0

Combine like terms: -2x + -3x = -5x
(3 + -5x + 2x2 + -9x2 + 6x3) = 0

Combine like terms: 2x2 + -9x2 = -7x2
(3 + -5x + -7x2 + 6x3) = 0

Solving
3 + -5x + -7x2 + 6x3 = 0

Solving for variable 'x'.

The solution to this equation could not be determined.

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